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author | Pasha <pasha@member.fsf.org> | 2023-01-27 00:54:07 +0000 |
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committer | Pasha <pasha@member.fsf.org> | 2023-01-27 00:54:07 +0000 |
commit | ef800d4ffafdbde7d7a172ad73bd984b1695c138 (patch) | |
tree | 920cc189130f1e98f252283fce94851443641a6d /glpk-5.0/examples/money.mod | |
parent | ec4ae3c2b5cb0e83fb667f14f832ea94f68ef075 (diff) | |
download | oneapi-ef800d4ffafdbde7d7a172ad73bd984b1695c138.tar.gz oneapi-ef800d4ffafdbde7d7a172ad73bd984b1695c138.tar.bz2 |
Diffstat (limited to 'glpk-5.0/examples/money.mod')
-rw-r--r-- | glpk-5.0/examples/money.mod | 62 |
1 files changed, 62 insertions, 0 deletions
diff --git a/glpk-5.0/examples/money.mod b/glpk-5.0/examples/money.mod new file mode 100644 index 0000000..e43ef39 --- /dev/null +++ b/glpk-5.0/examples/money.mod @@ -0,0 +1,62 @@ +/* MONEY, a crypto-arithmetic puzzle */ + +/* Written in GNU MathProg by Andrew Makhorin <mao@gnu.org> */ + +/* This is the classic example of a crypto-arithmetic puzzle published + in the Strand Magazine by Henry Dudeney: + + S E N D + + + M O R E + --------- + M O N E Y + + In this puzzle the same letters mean the same digits. The question + is: how to replace all the letters with the respective digits that + makes the calculation correct? + + The solution to this puzzle is: + O = 0, M = 1, Y = 2, E = 5, N = 6, D = 7, R = 8, and S = 9. + + References: + H. E. Dudeney, in Strand Magazine vol. 68 (July 1924), pp. 97, 214. + + (From Wikipedia, the free encyclopedia.) */ + +set LETTERS := { 'D', 'E', 'M', 'N', 'O', 'R', 'S', 'Y' }; +/* set of letters */ + +set DIGITS := 0..9; +/* set of digits */ + +var x{i in LETTERS, d in DIGITS}, binary; +/* x[i,d] = 1 means that letter i is digit d */ + +s.t. one{i in LETTERS}: sum{d in DIGITS} x[i,d] = 1; +/* each letter must correspond exactly to one digit */ + +s.t. alldiff{d in DIGITS}: sum{i in LETTERS} x[i,d] <= 1; +/* different letters must correspond to different digits; note that + some digits may not correspond to any letters at all */ + +var dig{i in LETTERS}; +/* dig[i] is a digit corresponding to letter i */ + +s.t. map{i in LETTERS}: dig[i] = sum{d in DIGITS} d * x[i,d]; + +var carry{1..3}, binary; +/* carry bits */ + +s.t. sum1: dig['D'] + dig['E'] = dig['Y'] + 10 * carry[1]; +s.t. sum2: dig['N'] + dig['R'] + carry[1] = dig['E'] + 10 * carry[2]; +s.t. sum3: dig['E'] + dig['O'] + carry[2] = dig['N'] + 10 * carry[3]; +s.t. sum4: dig['S'] + dig['M'] + carry[3] = dig['O'] + 10 * dig['M']; +s.t. note: dig['M'] >= 1; /* M must not be 0 */ + +solve; +/* solve the puzzle */ + +display dig; +/* and display its solution */ + +end; |