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authorPasha <pasha@member.fsf.org>2023-01-27 00:54:07 +0000
committerPasha <pasha@member.fsf.org>2023-01-27 00:54:07 +0000
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+/* GAP, Generalized Assignment Problem */
+
+/* Written in GNU MathProg by Andrew Makhorin <mao@gnu.org> */
+
+/* The Generalized Assignment Problem (GAP) is to assign a set of jobs
+ to a set of agents subject to the constraints that each job must be
+ assigned exactly to one agent and the total resources consumed by all
+ jobs assigned to an agent must not exceed the agent's capacity. */
+
+param m, integer, > 0;
+/* number of agents */
+
+param n, integer, > 0;
+/* number of jobs */
+
+set I := 1..m;
+/* set of agents */
+
+set J := 1..n;
+/* set of jobs */
+
+param a{i in I, j in J}, >= 0;
+/* resource consumed in allocating job j to agent i */
+
+param b{i in I}, >= 0;
+/* resource capacity of agent i */
+
+param c{i in I, j in J}, >= 0;
+/* cost of allocating job j to agent i */
+
+var x{i in I, j in J}, binary;
+/* x[i,j] = 1 means job j is assigned to agent i */
+
+s.t. one{j in J}: sum{i in I} x[i,j] = 1;
+/* job j must be assigned exactly to one agent */
+
+s.t. lim{i in I}: sum{j in J} a[i,j] * x[i,j] <= b[i];
+/* total amount of resources consumed by all jobs assigned to agent i
+ must not exceed the agent's capacity */
+
+minimize obj: sum{i in I, j in J} c[i,j] * x[i,j];
+/* the objective is to find cheapest assignment (note that gap can also
+ be formulated as maximization problem) */
+
+data;
+
+/* These data correspond to the instance c515-1 (gap1) from:
+
+ I.H. Osman, "Heuristics for the Generalised Assignment Problem:
+ Simulated Annealing and Tabu Search Approaches", OR Spektrum, Volume
+ 17, 211-225, 1995
+
+ D. Cattrysse, M. Salomon and L.N. Van Wassenhove, "A set partitioning
+ heuristic for the generalized assignment problem", European Journal
+ of Operational Research, Volume 72, 167-174, 1994 */
+
+/* The optimal solution is 261 (minimization) or 336 (maximization) */
+
+param m := 5;
+
+param n := 15;
+
+param a : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 :=
+ 1 8 15 14 23 8 16 8 25 9 17 25 15 10 8 24
+ 2 15 7 23 22 11 11 12 10 17 16 7 16 10 18 22
+ 3 21 20 6 22 24 10 24 9 21 14 11 14 11 19 16
+ 4 20 11 8 14 9 5 6 19 19 7 6 6 13 9 18
+ 5 8 13 13 13 10 20 25 16 16 17 10 10 5 12 23 ;
+
+param b := 1 36, 2 34, 3 38, 4 27, 5 33;
+
+param c : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 :=
+ 1 17 21 22 18 24 15 20 18 19 18 16 22 24 24 16
+ 2 23 16 21 16 17 16 19 25 18 21 17 15 25 17 24
+ 3 16 20 16 25 24 16 17 19 19 18 20 16 17 21 24
+ 4 19 19 22 22 20 16 19 17 21 19 25 23 25 25 25
+ 5 18 19 15 15 21 25 16 16 23 15 22 17 19 22 24 ;
+
+end;